Find:   [CBSE 2017]

[Applying the formula: sin² θ + cos² θ = 1]

Let sinθ = t

∴ cosθ dθ = dt

put t² = y and do the partial fractions,

∴ 1 = A(4y + 1) + B(y + 4) = (4A + B)y + (A + 4B)

Comparing coefficients of y on both sides-

4A + B = 0 ...(1)

Also compare constant terms-

A + 4B = 1 ...(2)

On solving (1) & (2), we get-

A = -(1/15) & B = (4/15)

put t = sinθ

Answer.