Q22 of 31 Page 7

Find:

  [CBSE 2016]






Using partial fraction:





On comparing:


A + B = 1 and 2B – A = 0


2B – A = 0


⇒ A = 2B


A + B = 1


⇒ 2B + B = 1


⇒ 3B = 1



Therefore,







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