Q29 of 31 Page 7

Evaluate:    [CBSE 2014]




We know that sin2x + cos2x = 1



We know that sin2x = 2sinxcosx



Divide numerator and denominator by cos22x




We know that 1 + tan2x = sec2x





Substitute tan2x = t


Differentiate with respect to x



⇒ dt = 2sec22xdx


Hence





Resubstitute t



Hence

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Using integration find the area of the triangle formed by positive x-axis and tangent and normal to the circle x2 + y2 = 4 at (1, √3).

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Evaluate

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[CBSE 2018]