Q14 of 29 Page 9

Find the particular solution of the differential equation given that y = 0 when x = 1.[CBSE 2014]





Integrate




To find the integration constant c we have given y = 0 when x = 1 hence put these (x, y) value




⇒ 0 = 2 + c


⇒ c = -2


Hence the solution will be






The solution of the given differential equation is


.

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