Find the particular solution of the differential equation
given that y = 0 when x = 1.[CBSE 2017]
The given equation is


This is a homogenous equation.
Now put y = vx
differentiate w.r.t x

∴ (1) becomes






Integrating both sides, we get-






put v = y/x



Now put y = 0 and x = 1



put the value of C in (2), we have-

This is the particular solution.
Couldn't generate an explanation.
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[CBSE 2013]