Find the particular solution of the differential equation
, given that y = π/4.
OR
Find the particular solution of the differential equation
, given that y = 0 when x = π/3.[CBSE 2018]
Given ![]()
![]()

ln |
= ln |tan y| + ln C
ln |
| = ln (C tan y )
= C tan y
Given x = 0, y = ![]()
= C tan ![]()
1 – 2 = C
1
C = – 1
= – tan y {since C = – 1}
+ tan y = 0.
OR
![]()
Let P =
and Q = ![]()
So, ![]()
I.F =
=
=
= ![]()
Soln. y(I.F) = ![]()
y![]()
y![]()
y![]()
Given y = 0 when x = ![]()
![]()
![]()
![]()
∴ y
{ since C = – 2}
y![]()
Couldn't generate an explanation.
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[CBSE 2016]

[CBSE 2013]