Solve the differential equation (x2 – y2) dx + 2xydy = 0.
OR
Find the particular solution of the differential equation
, given that y = 0 when x = 1.[CBSE 2018]
(x2 – y2) dx + 2xydy = 0

As this is a homogeneous differential equation thus,
Put ![]()
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Integrating both sides, we get,
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⇒log x = –log (1 + v2) + log c
⇒x (1 + v2) = c

⇒x2 + y2 = cx
OR
Given:
• At x = 1, y = 0
![]()
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This is in the form of first order linear differential equation hence,
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Therefore, solution is ![]()
At ![]()
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[CBSE 2013]