On a multiple choice examination with three possible answers (out of which only one is correct) for each of the five questions, what is the probability that a candidate would get four or more correct answers just by guessing?
This question is based on Bernoulli’s distribution.
Here the experiment is to get 4 or more correct answers by guessing n=5 questions.
There are three possible answers, P(getting correct answer)
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And P(getting wrong answer)
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Let X be the number of correct answers, then
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where x=0,1,….,n. and p+q=1
Now we have to calculate
P(getting 4 or more correct answers)=P(4)+P(5)
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Couldn't generate an explanation.
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