The points A(4, 5, 10), B(2, 3, 4) and C (1, 2, - 1) are three vertices of a parallelogram ABCD. Find the vector equations of the sides AB and BC and also find the coordinates of point D.
Let the coordinates of D be (x,y,z)
Direction vector along AB is
![]()
![]()
∴ Equation of line AB is:
![]()
Direction vector along BC is
![]()
![]()
∴ Equation of line BC is:
![]()
Since ABCD is a parallelogram AC and BD bisect each other.
![]()
⇒ 2 + x = 5, 3 + y = 7, 4 + z = 9
⇒ x = 3, y = 4, z = 5
Coordinates of D are (3,4,5).
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
