Prove the following:

OR
Prove the following:

Given that x ∈ (0, 1)
To Prove: ![]()
Proof: Take Right Hand Side (RHS),
![]()
Substitute x = tan2 θ in the above equation. We get
![]()
We know that, ![]()
Squaring on both sides, ![]()


![]()
We know that by trigonometric identity, sin2 θ + cos2 θ = 1.
![]()
Also, by trigonometric identity, cos 2θ = cos2 θ – sin2 θ.
![]()
And, cos-1(cos 2θ) = 2θ
![]()
⇒ RHS = θ …(i)
We had assumed x = tan2 θ
If x = tan2 θ
⇒ x = (tan θ)2
⇒ √x = tan θ
⇒ θ = tan-1 √x
So, substituting this value of θ in equation (i), we get
⇒ RHS = tan-1 √x
⇒ RHS = LHS
Hence, proved.
OR
We are given with a trigonometric equation.
To Prove: ![]()
Proof: Take Left Hand Side (LHS),
Let ![]()
…(i)
And let ![]()
…(ii)
Let us also find sin x and cos y.
We know the trigonometric identity,
sin2 x + cos2 x = 1
We need to find the value of sin x. So,
sin2 x = 1 – cos2 x
![]()
Substituting the value of cos x from (i),




…(iii)
Also,
sin2 y + cos2 y = 1
We need to find the value of cos y. So,
cos2 y = 1 – sin2 y
![]()
Substituting the value of sin y from (ii),




…(iv)
Now, we have the values of sin x, cos x, sin y and cos y.
Using trigonometric identity,
sin (x + y) = sin x cos y + cos x sin y
Substituting values of sin x, cos x, sin y and cos y from eq. (i), (ii), (iii) and (iv) respectively.
![]()
![]()
![]()
![]()
Substituting values of x and y,
![]()
⇒ LHS = RHS
Hence, proved.
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