Find the position vector of a point which divides the join of points with position vectors
and
externally in the ratio 2:1.
Given: two position vectors are ![]()
To find: position vector of the point which divided the join of points of given vectors in 2:1 externally
The formula used: The position vector of a point which divides the line of position vectors Y and X in the ratio m:n externally is given by,
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Let the required position vector be ![]()
Here m = 2, n = 1,![]()
Therefore,
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Hence, the required position vector is![]()
Couldn't generate an explanation.
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