Evaluate : 
To find:
We have,
Let f(x) = x3 – x = x(x2 – 1) = x(x – 1)(x + 1)
The signs for f(x) for the different values are shown in the figure below:
f(x) > 0 for all x 
(-1, 0) U (1, 2)
f(x) < 0 for all x 
(0, 1)
Therefore,
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