Find

OR

Evaluate

{∵ cos² x = 1 – sin² x}

Let sin θ = t

⇒ cos θ dθ = dt

t² – 4t + 4 = (t – 2)²

Using Partial function:

On compairing:

B = 3 and A – 2B = -2

A – 2(3) = -2

⇒ A – 6 = -2

⇒ A = 6 – 2

⇒ A = 4

Now, Put the value of t = sin θ:

where C is any constant

OR

To find:

Using integration by parts:

Again integrating by parts: