Find the vector equation of a plane which is at a distance of 5 units from the origin and its normal vector is ![]()
Given: A plane is at a distance of 5 units from the origin, and its normal vector is ![]()
To find: vector equation of the plane
Formula used:
The vector equation of the plane which is at a distance of d units from the origin and its normal vector is
is given by,
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So,
![]()
Here, d = 5 and ![]()
Hence, the vector equation of the plane is ![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
