Q12 of 45 Page 1

Show that:

OR


Solve the following equation:


To prove:


Let, y =


we can say that, we have to prove: tan y =


2y =


sin 2y = 3/4


As we know that: sin 2y =



8 tan y = 3 + 3 tan2y


3 tan2y – 8tan y + 3 = 0


tan y =


tan y =


tan y = or tan y =


Hence, tan y =


OR


Given:


We have to solve for x.


Let, y =


x = tan y


LHS = cos y =


As, RHS =


Let, cot-1(3/4) = θ


cot θ = 3/4


sin θ =


RHS = sin θ = 4/5


As, LHS = RHS {given}



5 = 4√(1+x2)


Squaring both sides, we have-


25 = 16(1+x2)


25 = 16 + 16x2


9 = 16x2


x2 = 9/16


x = ±√(9/16) = ±3/4


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