Show that: 
OR
Solve the following equation:

To prove: ![]()
Let, y = ![]()
∴ we can say that, we have to prove: tan y = ![]()
⇒ 2y = ![]()
⇒ sin 2y = 3/4
As we know that: sin 2y = ![]()
∴ ![]()
∴ 8 tan y = 3 + 3 tan2y
⇒ 3 tan2y – 8tan y + 3 = 0
⇒ tan y = ![]()
⇒ tan y = ![]()
∴ tan y =
or tan y = ![]()
Hence, tan y = ![]()
OR
Given: ![]()
We have to solve for x.
Let, y = ![]()
⇒ x = tan y
∴ LHS = cos y = ![]()
As, RHS = ![]()
Let, cot-1(3/4) = θ
∴ cot θ = 3/4
⇒ sin θ = ![]()
⇒ RHS = sin θ = 4/5
As, LHS = RHS {given}
⇒ ![]()
⇒ 5 = 4√(1+x2)
Squaring both sides, we have-
⇒ 25 = 16(1+x2)
⇒ 25 = 16 + 16x2
⇒ 9 = 16x2
⇒ x2 = 9/16
∴ x = ±√(9/16) = ±3/4
Couldn't generate an explanation.
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