In a hockey match, both teams A and B scored same number of goals up to the end of the game, so to decide the winner, the referee asked both the captains to throw a die alternately and decided that the team, whose captain gets a six first, will be declared the winner. If the captain of team A was asked to start, find their respective probabilities of winning the match and state whether the decision of the referee was fair or not.
As captain of team A has started to throw the die, he may win in the first throw or third or fifth and so on.
Team B can win in 2nd throw or 4th or 6th and so on
As probability of getting 6 on a die = 1/6 = P(6)
P(6’) represents event of not getting 6 = 5/6
Let P(A) represents the probability that team A wins the game and P(B) represents the probability that team B wins the game.
∴ P(A) = P(6) + P(6’)P(6’)P(6) + P(6’)P(6’)P(6’)P(6’)P(6)+…to ∞
⇒ P(A) = ![]()
⇒ P(A) = ![]()
Clearly it forms an infinite GP and sum of infinite GP is given by
where a is the first term and r is common ratio.
Here a = 1 and r = (5/6)2
∴ P(A) = 
Similarly,
P(B) = P(6’)P(6) + P(6’)P(6’)P(6’)P(6) + … to ∞
⇒ P(B) = ![]()
⇒ P(B) = ![]()
Clearly it forms an infinite GP and sum of infinite GP is given by
where a is the first term and r is common ratio.
Here a = 1 and r = (5/6)2
∴ P(B) = 
Clearly, P(A) > P(B)
Hence, there is more chance of winning of team A.
∴ Umpire’s decision is unfair. He has favoured team A.
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