Q19 of 45 Page 1

Evaluate :

Let, I = …(1)


Using the property of definite integral:


I =


I = { sin (2π – x) = -sin x}


I =


I = …(2)


Adding equation 1 and 2, we get –


2I =


Using algebra of integrals we have –


2I =


2I = = 2π – 0


I = π


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