Using properties of determinants, prove the following:

Let,
Δ = 
To prove: Δ = 9y2(x + y)
Applying C1 → C1 + C2 + C3, we get-
Δ = 
Taking (3x +3y) common from first column, we get
Δ = 
Applying R1 → R1 – R2, we get-
Δ = 
Applying R2 → R2 – R3, we get-
Δ = 
Expanding about 3rd row –
Δ = 3(x + y)![]()
⇒ Δ = 3(x + y)(y2 + 2y2)
⇒ Δ = 9y2(x + y)
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