If A and B are subsets of the universal set U, then show that
(i) A ⊂ A ∪ B
(ii) A ⊂ B ⇔ A ∪ B = B
(iii) (A ∩ B) ⊂ A
(i) Given: A and B are two subsets
To prove: A ⊂ A ∪ B
Let x ∈ A
⇒ x ∈ A or x ∈ B
⇒ x ∈ A ∪ B
⇒ A ⊂ A ∪ B
Hence Proved
(ii) Given: A and B are two sets
To prove: A ⊂ B ⇔ A ∪ B = B
Let x ∈ A ∪ B
⇒ x ∈ A or x ∈ B
⇒ x ∈ B {∵ A ⊂ B}
⇒ A ∪ B ⊂ B…………(1)
We know,
B ⊂ A ∪ B {this is always true}…………(2)
From (1) and (2):
A ∪ B = B
Now,
Let y ∈ A
⇒ y ∈ A ∪ B
⇒ y ∈ B {∵ A ∪ B = B}
⇒ A ⊂ B
So,
A ⊂ B ⇔ A ∪ B = B
Hence Proved
(iii) Given: A and B are two subsets
To prove: (A ∩ B) ⊂ A
Let x ∈ A ∩ B
⇒ x ∈ A and x ∈ B
⇒ x ∈ A
⇒ A ∩ B ⊂ A
Hence Proved
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