The set (A ∩ B′)′ ∪ (B ∩ C) is equal to
To find: (A ∩ B′)′ ∪ (B ∩ C)
(A ∩ B′)′ ∪ (B ∩ C)
= [A’ ∪ (B′)′] ∪ (B ∩ C)
{∵ (A ∩ B)’ = A’ ∪ B’}
= (A’ ∪ B) ∪ (B ∩ C)
{∵ (B’)’ = B}
= A’ ∪ (B ∪ (B ∩ C))
= A’ ∪ B
Hence, (A ∩ B′)′ ∪ (B ∩ C) = A’ ∪ B
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