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Q31 of 58 Page 12

The set (A ∩ B′)′ ∪ (B ∩ C) is equal to

To find: (A ∩ B′)′ ∪ (B ∩ C)


(A ∩ B′)′ ∪ (B ∩ C)


= [A’ ∪ (B′)′] ∪ (B ∩ C)


{∵ (A ∩ B)’ = A’ ∪ B’}


= (A’ ∪ B) ∪ (B ∩ C)


{∵ (B’)’ = B}


= A’ ∪ (B ∪ (B ∩ C))


= A’ ∪ B


Hence, (A ∩ B′)′ ∪ (B ∩ C) = A’ ∪ B

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Questions · 58
1. Sets
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