Suppose A1, A2, ..., A30 are thirty sets each having 5 elements and B1, B2, ..., Bn are n sets each with 3 elements, let
and each element of S belongs to exactly 10 of the Ai’s and exactly 9 of the B,’S. then n is equal to
Given: ![]()
To find: value of n
Since elements are not repeating, number of elements in A1∪ A2∪ A3∪ ………∪ A30 is 30 × 5
But each element is used 10 times
So, 10 × S = 30 × 5
⇒ 10 × S = 150
⇒ S = 15
Since elements are not repeating, number of elements in B1∪ B2∪ B3∪ ………∪ Bn is 3 × n
But each element is used 9 times
So, 9 × S = 3 × n
⇒ 9 × S = 3n
![]()
![]()
⇒ n = 45
Hence, the value of n is 45
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.