Let S = set of points inside the square, T = the set of points inside the triangle and C = the set of points inside the circle. If the triangle and circle intersect each other and are contained in a square. Then
Given: S = set of points inside the square, T = the set of points inside the triangle and C = the set of points inside the circle
Since, the triangle and circle intersect each other and are contained in a square.

Clearly, S ∪ T ∪ C = S
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