Q44 of 59 Page 178

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Equations of the lines through the point (3, 2) and making an angle of 45° with the line x – 2y = 3 are ____.

Given equation is:-

x – 2y = 3


x – 3 = 2y


…(i)


Now, we have to find the slope of eq. (i)


Since, the eq. (i) is in y = mx + b form.


So, slope of eq. (i) is



Now, we have to find the equation which is passing through the point (3, 2).


We know that, if a line passing through the point (x1, y1) then the equation of line is


y – y1 = m (x – x1)


So, here x1 = 3 and y1 = 2


y – 2 = m(x – 3) …(ii)


Now, it is given that the angle between the given two lines is 45°.



Putting the values of m1 and m2 in above eq., we get





2m – 1 = 2 + m or -(2m – 1) = 2 + m


2m – m = 2 + 1 or -2m + 1 – m = 2


m = 3 or -3m = 1


or


Putting the value of m = 3 in eq. (ii), we get


y – 2 = 3(x – 3)


y – 2 = 3x – 9


3x – y – 9 + 2 = 0


3x – y – 7 = 0


Putting the value of in eq. (ii), we get



3(y – 2) = 3 – x


3y – 6 = 3 – x


x + 3y – 6 – 3 = 0


x + 3y – 9 = 0


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