State whether the statements are true or false.
The vertex of an equilateral triangle is (2, 3) and the equation of the opposite side is x + y = 2. Then the other two sides are
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Let ABC be an equilateral triangle with vertex (2, 3)
and equation of opposite side is x + y = 2
We know that, all angle of an equilateral triangle is of 60°
So, θ = 60°
Let the slope of line AB is m
and slope of the given equation x + y = 2 is
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∴ m2 = -1
We know that,
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Putting the values of m1 and m2 in above eq., we get
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⇒ (1 – m)√3 = 1 + m or (1 – m)(-√3) = – 1 – m
⇒ √3 - √3 m = 1 + m or -√3 + √3 m = – 1 – m
⇒ √3 – 1 = m + √3m or -√3 + 1 = - m - √3m
⇒ √3 – 1 = m(1 + √3) or -(√3 – 1) = -m(√3 + 1)
…(i) or
…(ii)
Now, multiply and divide eq. (i) by √3 + 1, we get


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⇒ m = 2 + √3
Now, multiply and divide eq. (i) by √3 – 1 , we get


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⇒ m = 2 - √3
So, the slope of line AB is 2 ± √3
So, the equations of other two lines joining the point (2, 3) are
y – 3 = 2 ± √3 (x – 2)
Hence, the given statement is TRUE
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