If the letters of the word ALGORITHM are arranged at random in a row what is the probability the letters GOR must remain together as a unit?
Given word is ALGORITHM
⇒ Total number of letters in algorithm = 9
∴ Total number of words = 9!
So, n(S) = 9!
If ‘GOR’ remain together, then we consider it as one group.

∴ Number of letters = 7
Number of words, if ‘GOR’ remain together in the order = 7!
So, n(E) = 7!
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[∵ n! = n×(n – 1)×(n – 2)…1]
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