Q18 of 43 Page 296

In a non-leap year, the probability of having 53 Tuesdays or 53 Wednesdays is

In a non-leap year, there are 365 days and we know that there are 7 days in a week

∴ 365 ÷ 7 = 52 weeks + 1 day


This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday


∴ Total Outcomes = 7


If this day is a Tuesday or Wednesday, then the year will have 53 Tuesday or 53 Wednesday.


∴P(non-leap year has 53 Tuesdays or 53 Wednesdays)


Hence, the correct option is (B).

More from this chapter

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16

A sample space consists of 9 elementary outcomes e1, e2, ..., e9 whose probabilities are

P(e1) = P(e2) = .08, P(e3) = P(e4) = P(e5) = .1


P(e6) = P(e7) = .2, P(e8) = P(e9) = .07


Suppose A = {e1, e5, e8}, B = {e2, e5, e8, e9}


(a) Calculate P (A), P (B), and P (A ∩ B)


(b) Using the addition law of probability, calculate P (A ∪ B)


(c) List the composition of the event A ∪ B, and calculate P (A ∪ B) by adding the probabilities of the elementary outcomes.


(d) Calculate P () from P (B), also calculate P () directly from the elementary outcomes of .

17

Determine the probability p, for each of the following events.

(a) An odd number appears in a single toss of a fair die.


(b) At least one head appears in two tosses of a fair coin.


(c) A king, 9 of hearts, or 3 of spades appears in drawing a single card from a well shuffled ordinary deck of 52 cards.


(d) The sum of 6 appears in a single toss of a pair of fair dice.

 19

Three numbers are chosen from 1 to 20. Find the probability that they are not consecutive

 20

While shuffling a pack of 52 playing cards, 2 are accidentally dropped. Find the probability that the missing cards to be of different colours