The accompanying Venn diagram shows three events, A, B, and C, and also the probabilities of the various intersections (for instance, P (A ∩ B) = .07. Determine

(a) P (A)
(b) ![]()
(c) P (A ∪ B)
(d) P (A ∩ B)
(e) P (B ∩ C)
(f) Probability of exactly one of the three occurs.
Given P(A ⋂ B) = 0.07
From the given Venn Diagram
(a) P(A)

P(A) = 0.13 + 0.7 = 0.20
(b) ![]()
![]()
= 0.07 + 0.10 + 0.15 – 0.15
= 0.07 + 0.10
= 0.17
![]()
(c) P(A ⋃ B)
By General Addition Rule,
P(A ⋃ B) = P(A) + P(B) – P(A ⋂ B)
⇒ P(A ⋃ B) = 0.20 + (0.07 + 0.10 + 0.15) – 0.07
⇒ P(A ⋃ B) = 0.20 + 0.25
⇒ P(A ⋃ B) = 0.45
(d) ![]()
We know that,
![]()
= 0.20 – 0.07 [from part (a)]
= 0.13
(e) P(B ⋂ C)

P(B ⋂ C) = 0.15
(f) Probability of exactly one of the three occurs

P(exactly one of the three occurs) = 0.13 + 0.10 + 0.28
= 0.51
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