Four candidates A, B, C, D have applied for the assignment to coach a school cricket team. If A is twice as likely to be selected as B, and B and C are given about the same chance of being selected, while C is twice as likely to be selected as D, what are the probabilities that
(a) C will be selected?
(b) A will not be selected?
Given that A is twice as likely to be selected as B
i.e. P(A) = 2 P(B) …(i)
and C is twice as likely to be selected as D
i.e. P(C) = 2P(D) …(ii)
Now, B and C are given about the same chance
∴ P(B) = P(C) …(iii)
Since, sum of all probabilities = 1
∴ P(A) + P(B) + P(C) + P(D) = 1
⇒ P(A) + P(B) + P(B) + P(D) = 1 [from (iii)]
[from (i) & (ii)]
[from (iii)]
[from (i)]
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⇒ 9P(A) = 4
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(a) P(C will be selected) = P(C)
= P(B) [from(iii)]
[from(i)]
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(b) P(A will not be selected) = P(A’)
= 1 – P(A)
[By complement Rule]
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