If a, b, c are GP, then show that
,
are in AP.
To prove:
,
are in AP.
Given: a, b, c are in GP
Formula used: (i) ![]()
As, a, b, c are in GP
⇒ ![]()
Taking log both side ![]()
⇒ log b – log a = log c – log b
⇒ 2log b = log a + log c
Dividing by log m
⇒ ![]()
⇒ ![]()
⇒ ![]()
Whenever any number a,b,c are in AP then 2b = a+c, considering this and the above equation we can say that
,
are in AP
Hence proved
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.