Q14 of 104 Page 468

If a, b, c are in GP, prove that a3, b3, c3 are in GP

To prove: a3, b3, c3 are in GP


Given: a, b, c are in GP


Proof: As a, b, c are in GP


⇒ b2 = ac


Cubing both sides




= common ratio = r


From the above equation, we can say that a3, b3, c3 are in GP


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