The sum of first three terms of a GP is
and their product is 1. Find the common ratio and these three terms.
Let the first three terms of G.P. be ![]()
It is given that ![]()
⇒ ![]()
⇒ a = 1
And
![]()
⇒ ![]()
⇒
…(a = 1)
⇒ ![]()
⇒ 10(1 + r2) = 29r
⇒ 10r2 - 29r + 10 = 0
⇒ 10r2 - 25r - 4r + 10 = 0
⇒ 5r(2r - 5) - 2(2r - 5) = 0
⇒ (2r - 5)(5r - 2) = 0
⇒ r = ![]()
Therefore the first three terms are:
i)if r =
then
![]()
ii)if r =
then
![]()
Ans:Common ratio r =
and the first three terms are:
i)if r =
then
![]()
ii)if r =
then
![]()
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