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12. Geometrical Progression
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Q6 of 104 Page 488

Prove that 91/3 × 91/9 × 91/27 × …..∞ = 3

L.H.S=91/3 × 91/9 × 91/27 × …..∞


=9(1/3)+(1/9)+(1/27)+…∞


The series in the exponent is an infinite geometric series


Whose, a



∴Sum of the series in the exponent


∴L.H.S=91/2


=3=R.H.S


Hence, Proved that 91/3 × 91/9 × 91/27 × …..∞ = 3


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Questions · 104
12. Geometrical Progression
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 1 1 1 1 1 1 F 2 A 2 B 2 C 2 D 2 E 3 4 5 6 7 8 9 10 11 12 13 14 15 16 1 2 3 4 5 6 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 1 2 13 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13
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