Q16 of 169 Page 644

Find the area of ΔABC whose vertices are A(-3, -5), B(5, 2) and C(-9, -3).

Given: The vertices of the triangle are A(-3, -5), B(5, 2) and C(-9, -3).

Formula: Area of Δ ABC

Here,

x₁ = -3, y₁ = -5

x₂ = 5, y₂ = 2

x₃ = -9, y₃ = -3

Putting the values,

Area of Δ ABC

= 29 square units.

Therefore, the area of Δ ABC is 29 square units.

Show that the points A(2, -1), B(3, 4), C(-2, 3) and D(-3, -2) are the vertices of a rhombus.

If the points A (-2, -1), B(1, 0), C(x, 3) and D(1, y) are the vertices of a parallelogram, find the values of x and y.

Show that the points A(-5, 1), B(5, 5) and C(10, 7) are collinear.

Find the value of k for which the points A(-2, 3), B(1, 2) and C(k, 0) are collinear.