Q14 of 169 Page 703

Find the distance between the parallel lines 4x – 3y + 5 = 0 and 4x – 3y + 7 = 0

Given: parallel lines 4x – 3y + 5 = 0 and 4x – 3y + 7 = 0

To find : distance between the parallel lines

Formula used :

The distance between the parallel lines ax + by + c =0 and ax + by + d =0 is,

Here a = 4 ,b = -3 ,c = 5 ,d = 7

The distance between the parallel lines 4x – 3y + 5 = 0 and 4x – 3y + 7 = 0 is units

Find all the points on the line x + y = 4 that lie at a unit distance from the line 4x+3y=10.

A vertex of a square is at the origin and its one side lies along the line 3x – 4y – 10 = 0.

Find the area of the square.

Find the distance between the parallel lines 8x + 15y – 36 = 0 and 8x + 15y + 32 = 0.

Find the distance between the parallel lines y = mx + c and y = mx + d