Q2 of 169 Page 703

Find the distance of the point (-2, 3) from the line 12x = 5y + 13.

Given: Point (-2,3) and line 12x – 5y = 13


To find: The distance of the point (-2, 3) from the line 12x – 5y = 13


Formula used:


We know that the distance between a point P (m,n) and a line ax + by + c = 0 is given by,


D



The given equation of the line is 12x – 5y - 13=0


Here m= -2 and n = 3 , a = 12 , b = -5 , c = -13


D


D


D


The distance of the point (-2, 3) from the line 12x = 5y + 13 is 4 units


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9

Reduce each of the following equations to normal form :

(i) x + y - 2 = 0


(ii)


(iii) x + 5 = 0


(iv) 2y – 3 =0


(v) 4x + 3y - 9 = 0


 1

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 3

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 4

Find the distance of the point (2, 3) from the line y = 4.