Prove that the product of the lengths of perpendiculars drawn from the points
Given: Point
,
and line 
To Prove: The product of the lengths of perpendiculars drawn from the points
and
to the line
, is b2
Formula used:
We know that the length of the perpendicular from (m,n) to the line ax + by + c = 0 is given by,
D![]()
The equation of the line is ![]()
At point A, m=
and n=
, ![]()
D1
D1
At point B, m=
and n=
, ![]()
D2
D2
Product of the lengths of perpendiculars drawn from the points A and B is D1
D2
D1
D2
(In the numerator we have
and
)
D1
D2
D1
D2
D1
D2![]()
Product of the lengths of perpendiculars drawn from the points A and B is ![]()
Couldn't generate an explanation.
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