#Mark the correct alternative in each of the following
The maximum value of x1/x, x > 0 is
.
Let ![]()
therefore,
.
Differentiating w.r.t x
so,
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Now, lets put y’=0
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so
OR
1-log x) =0
therefore,x=1/e and x=0
Hence by second derivative test
f’’(1/e)<0 so it’s a point of maximum
and maximum value is
.
Couldn't generate an explanation.
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