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18. Maxima and Minima
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Q6 of 137 Page 18

Find the maximum and minimum values of f(x) = tan x – 2x.

we have


y = tanx – 2x


y’ = sec2x – 2


y’’ = 2sec2xtanx


For maxima and minima,


y’ = 0


sec2x = 2


secx = ±√2


x =


y’’() = 4 > 0


x = is the point of minima


y’’() = – 4 < 0


x = is the point of maxima


hence


max value = f() = – 1 –


min value = f() = 1 –


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18. Maxima and Minima
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