Find the maximum and minimum values of f(x) = tan x – 2x.
we have
y = tanx – 2x
y’ = sec2x – 2
y’’ = 2sec2xtanx
For maxima and minima,
y’ = 0
sec2x = 2
secx = ±√2
x = ![]()
y’’(
) = 4 > 0
x =
is the point of minima
y’’(
) = – 4 < 0
x =
is the point of maxima
hence
max value = f(
) = – 1 – ![]()
min value = f(
) = 1 – ![]()
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