Q3 of 137 Page 19

#Mark the correct alternative in each of the following

The minimum value of is




f’(x)=0



logx-1=0


⇒ x=e


for second derivative we find f’(x)



Hence by second derivative test


f’’(x)>0 so it’s a point of minimum.


therefore,




x=e is a point of minimum


so minimum value is f(e)=e

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