#Mark the correct alternative in each of the following

For the function

In such type of questions

find both the maximum and minimum value to compare the options.

so first,

so,

put f’(x)=0;

⇒ x=±1

Hence by second derivative test

f’’(x)>0 or f”(x)<0

so it’s a point of minimum or maximum respecctively.

f”(-1)=-2<0;

f”(1)=2>0

so x=1 is a point of minimum

and x=-1 is a point of maximum

f(1)=2 is minimum value.

f(-1)=-2 is maximum value.

therefore,

maximum value<minimum value.