Mark the Correct alternative in the following:
If
then sin 3x + sin 3y =
sin x + sin y = √3 (cos y – cos x)
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⇒ x + y = 0 or ![]()
⇒ x = -y
or ![]()
⇒ x = -y
or ![]()
Putting these values of x in sin 3x + sin 3y,
For x = -y
sin 3x + sin 3y
= sin 3(-y) + sin 3y
= -sin 3y + sin 3y
= 0
For ![]()
sin 3x + sin 3y
![]()
= sin (3y + π) + sin 3y
= -sin 3y + sin 3y
= 0
So, sin 3x + sin 3y = 0 (Ans)
Couldn't generate an explanation.
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