i. We know, 2 sin A sin B = cos (A – B) – cos (A + B)
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= cos 60° - cos 90°
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Hence Proved
ii. We know, 2 cos A cos B = cos (A + B) + cos (A – B)
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= cos 90° + cos 60°
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Hence Proved
iii. We know, 2 sin A cos B = sin (A + B) + sin (A – B) ![]()
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= sin 90° + sin 60°
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Hence Proved
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