Prove that:

Take L.H.S
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Multiplying & Dividing by 2:

{∵ 2 sin A sin B = cos (A – B) – cos (A + B)}
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{∵ cos (-A) = cos A}

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Multiplying & Dividing by 2:
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{∵ 2 cos A sin B = sin (A + B) – sin (A – B)}
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{∵ sin (-A) = - sin A}
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{∵ sin (180° - A) = sin A}
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= R.H.S
Hence Proved
Couldn't generate an explanation.
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