Q6 of 90 Page 8

Prove that :

Take L.H.S.


sin 3A + sin 2A – sin A


= (sin 3A – sin A) + sin 2A






{sin 2A = 2 sin A cos A}


= 2 cos 2A sin A + 2 sin A cos A


= 2 sin A (cos 2A + cos A)






= R.H.S.


Hence Proved


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