A 4% solution(w/w) of sucrose (M = 342 g mol-1) in water has a freezing point of 271.15 K. Calculate the freezing point of 5% glucose (M = 180 g mol–1) in water. (Given: Freezing point of pure water = 273.15 K).
4% solution (w/w) of sucrose means 4g of sucrose in 96g water
Wsolvent = 96g, wsolute= 4g, Msolute= 342 g mol-1
Using the formula, ∆Tf = kf x m
(273.15 – 271.15) = ![]()
Kf = 16.39 K
For 5% solution (w/w) of sucrose means 5g of sucrose in 95g water
Wsolvent = 95g, wsolute= 5g, Msolute= 180 g mol-1
Using the formula, ∆Tf = kf x m
∆Tf =
K
= 0.48 K
Tf = Tf0 - ∆Tf = (273.15 – 0.48) K = 272.67 K
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