Q4 of 91 Page 230

An experimenter’s diary reads as follow: “a charged particle is projected in a magnetic field of The acceleration of the particle is found to be The number to the left of in in the last expression was not readable. What can this number be?

Given-


Magnetic field,


Acceleration of the particle,


Let denoted the unidentified number as


Since, magnetic force always acts perpendicular to the motion of


the particle, so, B and a are perpendicular to each other.


So, the dot product of the two quantities should be zero.



That is,








Hence acceleration of the particle is m/s2.


More from this chapter

All 91 →
2

An electron is projected horizontally with a kinetic energy of 10 keV. A magnetic filed of strength 1.0 × 10–7 T exists in the vertically upward direction.

(a) Will the electron deflect toward right or towards left of its motion?


(b) Calculate the sideways deflection of the electron in travelling through 1m. Make appropriate approximations.


 3

A magnetic field of (4.0 x 10-3 vector k)T exerts a force of (4.0 vector i + 3.0 vector j) x 10-10N on a particle having a charge of 1.0 x 10-9C and going in the X-Y plane. Find the velocity of the particle.

 5

A 10 g bullet having a charge of 4.00 μC is fired at a speed of 270 ms–1 in a horizontal direction. A vertical magnetic field of 500 μT exists in the space. Find the deflection of the bullet due to the magnetic field as it travels through 100 m. Make appropriate approximations.

 6

When a proton is released from rest in a room, it starts with an initial acceleration a0 towards west. When it is projected towards north with a sped v0, it moves with an initial acceleration 3a0 towards west. Find the electric field and the minimum possible magnetic field in the room.