A body of mass 0.5 kg travels in a straight line with velocity v = a x3/2 where a = 5 m-1/2 s-1. The work done by the net force during its displacement from x = 0 to x = 2 m is
Given, ![]()
Initial velocity, u (at x=0) =0
Final velocity ,v(at x=2m)=![]()
Work done=change in kinetic velocity
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Option (b) is correct.
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