Q42 of 48 Page 46

An adult weighing 600N raises the centre of gravity of his body by 0.25 m while taking each step of 1 m length in jogging. If he jogs for 6 km, calculate the energy utilised by him in jogging assuming that there is no energy loss due to friction of ground and air. Assuming that the body of the adult is capable of converting 10% of energy intake in the form of food, calculate the energy equivalents of food that would be required to compensate energy utilised for jogging.

1 step is of 1 m


in 6km there are 6000 steps


Person raises the body by 0.25 m in each step


Work done in each step =


total work in 6000 steps


W=


W = 10% of food energy


Food energy = 10× W=


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(c) increase in potential energy


(d) increase in kinetic energy


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