Q10 of 124 Page 1

Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21.

Required number must be divisible by the LCM of 8, 15 and 21 i.e., by 840


Now on dividing 110000 by LCM we get 800 as remainder.


Therefore the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21 = 110000 – Remainder ⇒ 110000 – 800 = 109200


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