Q11 of 124 Page 1

The HCF of 95 and 152, is

We know that HCF = Product of the smallest power of each common prime factor in the numbers.

The prime factorization of

95 = 5 × 19

And 152 = 2³ × 19

∴ HCF = 19

If two positive integers m and n are expressible in the form m = pq³ and n = p³ q² where p, q are prime numbers, then HCF (m, n) =

If the LCM of a and 18 is 36 and the HCF of a and 18 is 2, then a =

If HCF (26, 169) = 13, then LCM (26, 169) =

If a = 2³ × 3, b = 2 × 3 × 5, c = 3ⁿ × 5 and LCM (a, b, c) = 2³ × 3² × 5, then n =